25v^2+35v=-6

Solution for 25v^2+35v=-6 equation:

25v^2+35v=-6

We move all terms to the left:

25v^2+35v-(-6)=0

We add all the numbers together, and all the variables

25v^2+35v+6=0

a = 25; b = 35; c = +6;
Δ = b2-4ac
Δ = 352-4·25·6
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-25}{2*25}=\frac{-60}{50}
=-1+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+25}{2*25}=\frac{-10}{50}
=-1/5
$